$$\int_0^1e^{\mbox{max}\{x,1-x\}}dx$$.
First we'll split up the region of integration into two pieces, one where $x$ is larger and one where $1-x$ is larger. Observe that $1-x$ is larger on the interval $[0,1/2]$ and $x$ is larger on the interval $[1/2,1]$. So we can write
$$\int_0^1e^{\mbox{max}\{x,1-x\}}dx=\int_{0}^{1/2}e^{1-x}dx+\int_{1/2}^1 e^xdx,$$
which are fairly simple.
2. The hint written on the assignment is sufficient.
3. Use the formula for 4 dimensional volume(similar to the one for area).
$$V(D)=\iiiint_{D}dV,$$
and use change of variables to write
$$dV=\left|\frac{\partial(x,y,z,w)}{\partial(r,\theta,s,\varphi)}\right|,$$
and use the technique here to take the determinant. Be careful about the bounds of integration for $r$ and $s$.
Thats all for now, we'll have the technology to solve 4 and 5 after this week.
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